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Question 39 of 48

Q.Find the value of 100C99^{100}C_{99} :

(a) 11
(b) 100100
(c) 00
(d) 9999
Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2024MCQ· 1mImportance★★★★★
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100C99=100^{100}C_{99}=100.

Use the property nCr=nCn−r^nC_r={}^nC_{n-r}, which lets us replace a large lower index by a small one:

100C99=100C100−99=100C1.^{100}C_{99}={}^{100}C_{100-99}={}^{100}C_{1}. …

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