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Exercises · Q8

Q.The demand function for a product is x=200−4px = 200 - 4p. At p=30p=30, determine whether demand is elastic, inelastic, or unit elastic, and state what would happen to total revenue if the price were increased slightly.

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✓ Free question

Step 1 — Find xx at p=30p=30. x=200−4(30)=200−120=80x = 200-4(30) = 200-120=80.

Step 2 — Differentiate the demand function. x=200−4p⇒dxdp=−4x=200-4p \Rightarrow \dfrac{dx}{dp}=-4.

Step 3 — Apply the elasticity formula.

ed=−px⋅dxdp=−3080×(−4)=12080=1.5e_d = -\dfrac{p}{x}\cdot\dfrac{dx}{dp} = -\dfrac{30}{80}\times(-4) = \dfrac{120}{80} = 1.5

Step 4 — Classify and interpret. Since ed=1.5>1e_d=1.5>1, demand is elastic at p=30p=30. For elastic demand, a price rise causes a proportionally larger fall in quantity demanded, so total revenue R=xpR=xp decreases when price is increased (and would increase if price were instead reduced).

Independent check. Compute total revenue at p=30p=30 and at a slightly higher price, say p=31p=31: R(30)=80×30=2400R(30)=80\times30=2400. At p=31p=31: x=200−124=76x=200-124=76, so R(31)=76×31=2356R(31)=76\times31=2356. Since RR fell from 24002400 to 23562356 as price rose from 3030 to 3131, this directly confirms the elastic-demand prediction that a price increase reduces total revenue.

✓Final answer

ed=1.5e_d=1.5, so demand is elastic at p=30p=30; increasing the price would decrease total revenue (confirmed directly: revenue falls from 24002400 to 23562356 as price rises from 3030 to 3131).

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