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Exercises · Q7

Q.Find the standard deviation and coefficient of variation of the following data: 10, 12, 14, 16, 18.

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✓ Free question

Step 1 — Find the mean. xˉ=10+12+14+16+185=705=14\bar x = \dfrac{10+12+14+16+18}{5} = \dfrac{70}{5}=14.

Step 2 — Find the deviations from the mean and square them.

xxx−xˉx-\bar x(x−xˉ)2(x-\bar x)^2
10−416
12−24
1400
1624
18416
Total40

Step 3 — Find the standard deviation. σ=405=8≈2.83\sigma = \sqrt{\dfrac{40}{5}} = \sqrt{8} \approx 2.83.

Step 4 — Find the coefficient of variation. CV=σxˉ×100=2.8314×100≈20.2%CV = \dfrac{\sigma}{\bar x}\times100 = \dfrac{2.83}{14}\times100 \approx 20.2\%.

Independent check (direct/raw-score method). σ2=∑x2n−xˉ2\sigma^2 = \dfrac{\sum x^2}{n}-\bar x^2. ∑x2=100+144+196+256+324=1020\sum x^2 = 100+144+196+256+324=1020. 10205−142=204−196=8\dfrac{1020}{5}-14^2 = 204-196=8, so σ=8≈2.83\sigma=\sqrt{8}\approx2.83 — matches Step 3 exactly, confirming via the alternative raw-score formula.

✓Final answer

Standard deviation ≈2.83\approx2.83; coefficient of variation ≈20.2%\approx20.2\%.

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