If A and B are independent events $P(A) = \dfrac{2}{5}$ and $P(B) = \dfrac{1}{5}$ then $P(A \cap B)$ : (a) $0$ (b) $\dfrac{3}{25}$ (c) $\dfrac{1}{25}$ (d) $\dfrac{2}{25}$

If A and B are independent events P(A) = (2)/(5) and P(B) = (1)/(5) then P(A ∩ B) : (a) 0 (b) (3)/(25) (c) (1)

Question 13 of 34

P(A) = \dfrac{2}{5}

(a)

0

(b)

\dfrac{3}{25}

(c)

\dfrac{1}{25}

(d)

\dfrac{2}{25}

Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2020MCQ· 1mImportance★★★★★

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Because $A$ and $B$ are independent, $P(A\cap B)=P(A)P(B)=\dfrac{2}{5}\cdot\dfrac{1}{5}=\dfrac{2}{25}$ .

Two events $A$ and $B$ are independent when the occurrence of one does not affect the probability of the other. For such events the multiplication rule simplifies to:

$P(A\cap B) = P(A)\cdot P(B).$ …

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Q.If A and B are independent events $P(A) = \dfrac{2}{5}$ and $P(B) = \dfrac{1}{5}$ then $P(A \cap B)$ :

Concept understanding — Conditional Probability and Independent Events

Q.If A and B are independent events P(A)=25P(A) = \dfrac{2}{5}P(A)=52​ and P(B)=15P(B) = \dfrac{1}{5}P(B)=51​ then P(A∩B)P(A \cap B)P(A∩B) :

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Q.If A and B are independent events $P(A) = \dfrac{2}{5}$ and $P(B) = \dfrac{1}{5}$ then $P(A \cap B)$ :

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