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Worked Examples · Example 9

Q.Evaluate lim⁡x→∞(1+2x)x\displaystyle\lim_{x\to\infty}\left(1+\dfrac{2}{x}\right)^{x}.

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Step 1 — Substitute to match the standard form. The standard limit is lim⁡m→∞(1+1m)m=e\lim_{m\to\infty}\left(1+\dfrac1m\right)^m=e. Here we have 2x\dfrac2x in place of 1m\dfrac1m, so let m=x2m=\dfrac{x}{2} (equivalently x=2mx=2m); then 2x=1m\dfrac{2}{x}=\dfrac{1}{m}, and as x→∞x\to\infty, m→∞m\to\infty as well.

Step 2 — Rewrite the expression.

(1+2x)x=(1+1m)2m=[(1+1m)m]2\left(1+\frac2x\right)^x = \left(1+\frac1m\right)^{2m} = \left[\left(1+\frac1m\right)^m\right]^2

Step 3 — Apply the standard limit. As m→∞m\to\infty, (1+1m)m→e\left(1+\dfrac1m\right)^m \to e, so the whole expression tends to e2e^2. …

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