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Business Mathematics and Statistics · Ch 4 — Trigonometry

Multiple and Sub-multiple Angles

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Multiple and Sub-multiple Angles

Setting B=AB=A in the compound-angle formulae of the previous section gives the double-angle (multiple-angle) formulae:

sin⁡2A=2sin⁡Acos⁡A\sin 2A = 2\sin A\cos A

cos⁡2A=cos⁡2A−sin⁡2A=2cos⁡2A−1=1−2sin⁡2A\cos 2A = \cos^2A - \sin^2A = 2\cos^2A - 1 = 1 - 2\sin^2A

tan⁡2A=2tan⁡A1−tan⁡2A\tan 2A = \frac{2\tan A}{1 - \tan^2A}

(The three forms of cos⁡2A\cos 2A are all equivalent — obtained from each other using sin⁡2A+cos⁡2A=1\sin^2A+\cos^2A=1 — and it is worth being comfortable switching between them, since a problem may be easier to finish with one form than another.)

Running the same substitution the other way — replacing AA by A2\tfrac{A}{2} throughout — gives the sub-multiple (half-angle) forms, used when the original angle AA is known but the ratio of half that angle is required:

sin⁡A=2sin⁡A2cos⁡A2,cos⁡A=cos⁡2A2−sin⁡2A2,tan⁡A=2tan⁡A21−tan⁡2A2\sin A = 2\sin\tfrac{A}{2}\cos\tfrac{A}{2}, \qquad \cos A = \cos^2\tfrac{A}{2} - \sin^2\tfrac{A}{2}, \qquad \tan A = \frac{2\tan\tfrac{A}{2}}{1-\tan^2\tfrac{A}{2}} …

Definition 1Double-Angle Formulae

sin⁡2A=2sin⁡Acos⁡A\sin2A=2\sin A\cos A; cos⁡2A=cos⁡2A−sin⁡2A=2cos⁡2A−1=1−2sin⁡2A\cos2A=\cos^2A-\sin^2A=2\cos^2A-1=1-2\sin^2A; $\tan2A=\dfrac{2\ta …

Definition 2Sub-multiple (Half-Angle) Forms

The same double-angle relations written with AA replaced by A/2A/2 throughout, e.g. $\sin A = 2\s …