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Exercise 2.12 · Q12

Q.Solve log⁡5−x(x2−6x+65)=2\log_{5-x}(x^2-6x+65)=2.

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Step 1. Convert to exponential form: (5−x)2=x2−6x+65(5-x)^2=x^2-6x+65.

Step 2. Expand the left side: 25−10x+x2=x2−6x+6525-10x+x^2=x^2-6x+65.

Step 3. Simplify: 25−10x=−6x+65⇒−4x=40⇒x=−1025-10x=-6x+65\Rightarrow-4x=40\Rightarrow x=-10. …

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