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Exercise 4.1 · Q1

Q.(i) A person went to a restaurant for dinner. In the menu card, the person saw 10 Indian and 7 Chinese food items. In how many ways the person can select either an Indian or a Chinese food?

(ii) There are 3 types of toy car and 2 types of toy train available in a shop. Find the number of ways a baby can buy a toy car and a toy train?
(iii) How many two-digit numbers can be formed using 1,2,3,4,51,2,3,4,5 without repetition of digits?
(iv) Three persons enter into a conference hall in which there are 10 seats. In how many ways they can take their seats?
(v) In how many ways 5 persons can be seated in a row?
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✓ Free question

Each part is a direct application of the Sum Rule, the Product Rule, or the arrangement formulas nPr=n!(n−r)!^nP_r=\dfrac{n!}{(n-r)!} and n!n!.

Step 1. (i) Selecting either an Indian or a Chinese item are non-simultaneous alternatives, so by the Sum Rule: 10+7=1710+7=17 ways.

Step 2. (ii) Buying a car and a train are two independent procedures done together, so by the Product Rule: 3×2=63\times2=6 ways.

Step 3. (iii) A two-digit number from {1,2,3,4,5}\{1,2,3,4,5\} without repetition: tens place has 55 choices, units place has 44 remaining choices ⇒5×4=5P2=20\Rightarrow 5\times4={}^5P_2=20.

Step 4. (iv) 33 persons taking 33 of the 1010 distinct seats (order matters — which seat each person takes): 10P3=10×9×8=720^{10}P_3=10\times9\times8=720.

Step 5. (v) 55 persons seated in a row (all 55 arranged): 5!=1205!=120.

✓Final answer

(i) 1717 (ii) 66 (iii) 2020 (iv) 720720 (v) 120120.

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