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Question 103 of 134

Q.How many numbers divisible by 5 and lying between 5000 and 6000 can be formed from the digits 5, 6, 7, 8 and 9 ?

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2018Subjective· 2mImportance★★★★★
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The number must start and end in 5 (digits may repeat), leaving the two middle positions free to be any of the 5 digits each, giving 5×5=255\times5=25 numbers.

A 4-digit number lying strictly between 5000 and 6000 must have its first (thousands) digit equal to 5.

For the number to be divisible by 5, its last (units) digit must be 0 or 5. Since 0 is not among the available digits {5,6,7,8,9}\{5,6,7,8,9\}, the units digit must be 5.

So the first digit is fixed as 5 and the last digit is fixed as 5 (digits may repeat across positions, since the set only offers one 5 and it's being reused in two positions).

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