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Exercise 10.5 · Q16

Q.If pv=81pv = 81, then dpdv\dfrac{dp}{dv} at v=9v=9 is

(1) 1
(2) −1-1
(3) 2
(4) −2-2
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Step 1. From pv=81pv=81, express pp as a function of vv: p=81v=81v−1p=\dfrac{81}{v}=81v^{-1}.

Step 2. Differentiate:

dpdv=−81v−2=−81v2\frac{dp}{dv}=-81v^{-2}=-\frac{81}{v^2}

Step 3. Evaluate at v=9v=9: …

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