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Exercise 9.6 · Q13

Q.lim⁡x→0xex−sin⁡xx\displaystyle\lim_{x\to0}\dfrac{xe^x-\sin x}{x} is

(1) 11
(2) 22
(3) 33
(4) 00
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Step 1. Split the fraction: xex−sin⁡xx=xexx−sin⁡xx=ex−sin⁡xx\dfrac{xe^x-\sin x}{x}=\dfrac{xe^x}{x}-\dfrac{\sin x}{x}=e^x-\dfrac{\sin x}{x}.

Step 2. As x→0x\to0, ex→1e^x\to1 (continuity of exe^x). …

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