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Exercise 12.1 · Q9

Q.A cricket club has 16 members, of whom only 5 can bowl. What is the probability that in a team of 11 members at least 3 bowlers are selected?

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Step 1. Total ways to form a team. n(S)=(1611)=(165)=4368n(S)=\binom{16}{11}=\binom{16}{5}=4368.

Step 2. Favourable teams (at least 3 of the 5 bowlers). Since only 5 bowlers and 16−5=1116-5=11 non-bowlers exist, and the team needs 11 members with at least 3 bowlers, the number of bowlers kk can be 3, 4, or 5:

k=3k=3: (53)(118)=10×165=1650\binom53\binom{11}{8}=10\times165=1650.

k=4k=4: (54)(117)=5×330=1650\binom54\binom{11}{7}=5\times330=1650.

k=5k=5: (55)(116)=1×462=462\binom55\binom{11}{6}=1\times462=462.

Total favourable =1650+1650+462=3762=1650+1650+462=3762. …

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