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Exercise 6.1 · Q3

Q.If θ\theta is a parameter, find the equation of the locus of a moving point, whose coordinates are x=acos⁡3θ, y=asin⁡3θx = a\cos^3\theta,\ y = a\sin^3\theta.

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✓ Free question

Isolate cos⁡θ\cos\theta and sin⁡θ\sin\theta, then use cos⁡2θ+sin⁡2θ=1\cos^2\theta+\sin^2\theta=1.

Step 1. Set up the coordinate equations. x=acos⁡3θx=a\cos^3\theta and y=asin⁡3θy=a\sin^3\theta, so

xa=cos⁡3θ,ya=sin⁡3θ.\frac{x}{a}=\cos^3\theta, \qquad \frac{y}{a}=\sin^3\theta.

Step 2. Solve for cos⁡θ\cos\theta and sin⁡θ\sin\theta. Taking the cube root of each,

cos⁡θ=(xa)1/3,sin⁡θ=(ya)1/3.\cos\theta=\left(\frac{x}{a}\right)^{1/3}, \qquad \sin\theta=\left(\frac{y}{a}\right)^{1/3}.

Step 3. Square both and add. cos⁡2θ=(xa)2/3\cos^2\theta=\left(\dfrac{x}{a}\right)^{2/3} and sin⁡2θ=(ya)2/3\sin^2\theta=\left(\dfrac{y}{a}\right)^{2/3}, and since cos⁡2θ+sin⁡2θ=1\cos^2\theta+\sin^2\theta=1:

(xa)2/3+(ya)2/3=1.\left(\frac{x}{a}\right)^{2/3}+\left(\frac{y}{a}\right)^{2/3}=1.

Step 4. Clear the common denominator. Multiplying through by a2/3a^{2/3}:

x2/3+y2/3=a2/3.x^{2/3}+y^{2/3}=a^{2/3}.

This curve is the astroid.

✓Final answer

x2/3+y2/3=a2/3x^{2/3}+y^{2/3}=a^{2/3}

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