Q.A particle's position moves from r1=3i^+4j^ to r2=i^+2j^. Calculate the displacement vector Δr and draw r1, r2 and Δr in a two dimensional Cartesian coordinate system.
Displacement Magnitude — The Straight-Line Shortcut
Imagine you walk 3 steps east, then 4 steps north. You end up at a spot that's not 7 steps away from where you started — it's only 5 steps away, diagonally. That 5 steps is your displacement magnitude.
Here's the core idea: displacement magnitude is the straight-line distance between where you began and where you ended. It doesn't care about the twists and turns of your actual path. It's the "as the crow flies" distance.
The Precise Definition
Displacement is a vector — it has both a direction and a magnitude. The magnitude of displacement (often written as ∣s∣ or simply s) is the length of that vector. Mathematically, if your initial position is (x1,y1) and your final position is (x2,y2), then:
∣s∣=(x2−x1)2+(y2−y1)2
This is just the distance formula from coordinate geometry. For the 3-step east, 4-step north example:
∣s∣=32+42=9+16=25=5 units
Watch out
Never confuse displacement magnitude with total distance travelled. In the example above, the total distance walked was 3+4=7 units, but the displacement magnitude was only 5 units. They are equal only when you move in a perfectly straight line without changing direction.
Why This Matters in Physics
In kinematics problems, displacement magnitude tells you the net effect of motion. When a car drives around a circular track and returns to the starting point, its displacement magnitude is zero — even though it travelled hundreds of metres. The car ended up exactly where it began.
For motion along a straight line (say, the x-axis), the displacement magnitude simplifies to:
∣s∣=∣x2−x1∣
That's just the absolute difference between final and initial positions. No square roots needed.
A Quick Check
If a particle moves from x=2 m to x=−3 m, what's the displacement magnitude?
The displacement vector is s=(−3−2)=−5 m. Its magnitude is ∣−5∣=5 m. The negative sign only tells you the direction (leftwards), but the magnitude — the distance between the two points — is 5 metres.
Important
Displacement magnitude is always non-negative. It's a length, and lengths can't be negative. The sign of the displacement vector tells you direction; the magnitude tells you how far apart the start and end points actually are.
Looking up "Displacement Magnitude: definition, formula & real-world examples" is a good habit before an exam, and it is worth knowing that Displacement Magnitude is a core, NCERT-aligned topic from the Motion in a Straight Line portion of the Class 11 Physics curriculum, and it is tested regularly in CBSE board exams as well as in JEE Main and NEET. Cross-checking this explanation against the relevant NCERT Physics chapter and solving a few past-year questions will round out your preparation.
Δr=r2−r1, subtract components.
✓Final answer
Δr=−2i^−2j^
Step 1. Given r1=3i^+4j^ and r2=i^+2j^.
Step 2.Δr=r2−r1=(1−3)i^+(2−4)j^=−2i^−2j^.
Step 3. Geometrically: plot r1 as an arrow from the origin to (3,4), r2 as an arrow from the origin to (1,2), and Δr as the arrow drawn directly from the tip of r1, (3,4), to the tip of r2, (1,2) — pointing down and to the left, consistent with the components (−2,−2).
✓Final answer
Δr=r2−r1=−2i^−2j^ (magnitude 22 m, directed from (3,4) to (1,2)).
Computing r₁ − r₂ instead of r₂ − r₁ (displacement is always final minus initial)