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Physics · Ch 2 — Kinematics

Subtraction of Vectors

2.3.4

Subtraction of Vectors

Vector subtraction is not a new operation — it is addition of a reversed vector. To find A⃗−B⃗\vec A - \vec B, first construct −B⃗-\vec B (same magnitude as B⃗\vec B, opposite direction), then apply the ordinary triangle law of addition to A⃗\vec A and −B⃗-\vec B:

A⃗−B⃗=A⃗+(−B⃗)\vec A - \vec B = \vec A + (-\vec B)

If θ\theta is the angle between A⃗\vec A and B⃗\vec B, then the angle between A⃗\vec A and −B⃗-\vec B is 180°−θ180° - \theta. Substituting 180°−θ180°-\theta in place of θ\theta in the addition formula (and using cos⁡(180°−θ)=−cos⁡θ\cos(180°-\theta) = -\cos\theta, sin⁡(180°−θ)=sin⁡θ\sin(180°-\theta)=\sin\theta) gives:

∣A⃗−B⃗∣=A2+B2−2ABcos⁡θ|\vec A - \vec B| = \sqrt{A^2 + B^2 - 2AB\cos\theta}

tan⁡α2=Bsin⁡θA−Bcos⁡θ\tan\alpha_2 = \frac{B\sin\theta}{A - B\cos\theta}

where α2\alpha_2 is the angle the difference vector makes with A⃗\vec A. Notice the only change from the addition formulas is the sign in front of the 2ABcos⁡θ2AB\cos\theta (and Bcos⁡θB\cos\theta) term — subtraction is 'addition with the angle supplemented'. …

Figure 2.19Subtraction of vectors

What this figure shows. Vectors A⃗\vec A and B⃗\vec B drawn from a common point, together with −B⃗-\vec B (the reverse of B⃗\vec B); the triangle law applied to A⃗\vec A and −B⃗-\vec B gives R⃗′=A⃗−B⃗\vec R' = \vec A - \vec B, shown alongside the ordinary sum R⃗=A⃗+B⃗\vec R = \vec A + \vec B for comparison, with the angle 180°−θ180°-\theta between A⃗\vec A …