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Exercises · Q8

Q.Evaluate ∫(3x+2)4 dx\int(3x+2)^4\,dx using substitution.

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Substituting

Let u=3x+2u=3x+2, so du=3 dxdu=3\,dx, i.e. dx=du3dx=\frac{du}{3}.

∫(3x+2)4 dx=∫u4⋅du3=13⋅u55+C=u515+C=(3x+2)515+C\int(3x+2)^4\,dx=\int u^4\cdot\frac{du}{3}=\frac13\cdot\frac{u^5}{5}+C=\frac{u^5}{15}+C=\frac{(3x+2)^5}{15}+C

Check (differentiate the answer back, using the chain rule): ddx[(3x+2)515]=5(3x+2)4⋅315=(3x+2)4\frac{d}{dx}\left[\frac{(3x+2)^5}{15}\right]=\frac{5(3x+2)^4\cdot3}{15}=(3x+2)^4 — exactly the original integrand.

✓Final answer

(3x+2)515+C\dfrac{(3x+2)^5}{15}+C

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