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Worked Examples · Example 2

Q.Evaluate ∫(2x+3)5 dx\int(2x+3)^5\,dx using substitution.

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✓ Free question

Substituting

Let u=2x+3u=2x+3, so du=2 dxdu=2\,dx, i.e. dx=du2dx=\frac{du}{2}.

∫(2x+3)5 dx=∫u5⋅du2=12∫u5 du=12⋅u66+C=u612+C=(2x+3)612+C\int(2x+3)^5\,dx=\int u^5\cdot\frac{du}{2}=\frac12\int u^5\,du=\frac12\cdot\frac{u^6}{6}+C=\frac{u^6}{12}+C=\frac{(2x+3)^6}{12}+C

Check (differentiate the answer back, using the chain rule): ddx[(2x+3)612]=6(2x+3)5⋅212=(2x+3)5\frac{d}{dx}\left[\frac{(2x+3)^6}{12}\right]=\frac{6(2x+3)^5\cdot2}{12}=(2x+3)^5 — exactly the original integrand.

✓Final answer

(2x+3)612+C\dfrac{(2x+3)^6}{12}+C

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