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Question 26 of 42

Q.(a) Find the consumer's surplus and producer's surplus for the demand function Pd=25−3xP_d=25-3x and supply function Ps=5+2xP_s=5+2x.

(OR)
(b) X is normally distributed with mean 12 and S.D 4. Find P(X≤20)P(X\le 20) and P(0≤X≤12)P(0\le X\le 12) [P(0<Z<2)=0.4772][P(0<Z<2)=0.4772]
Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2023Subjective· 5mImportance★★★★★
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(a) x0=4, p0=13x_0=4,\ p_0=13: CS =24=24, PS =16=16. (b) P(X≤20)=0.9772, P(0≤X≤12)=0.4987P(X\le20)=0.9772,\ P(0\le X\le12)=0.4987.

(a) Consumer's and producer's surplus. Pd=25−3x, Ps=5+2xP_d=25-3x,\ P_s=5+2x.

Equilibrium (set Pd=PsP_d=P_s): 25−3x=5+2x⇒20=5x⇒x0=425-3x=5+2x\Rightarrow 20=5x\Rightarrow x_0=4, and p0=25−3(4)=13p_0=25-3(4)=13.

Consumer's surplus:

CS=∫0x0Pd dx−x0p0=∫04(25−3x) dx−4(13).CS=\int_0^{x_0}P_d\,dx-x_0p_0=\int_0^4(25-3x)\,dx-4(13).

∫04(25−3x) dx=[25x−3x22]04=100−24=76.\int_0^4(25-3x)\,dx=\Big[25x-\frac{3x^{2}}{2}\Big]_0^4=100-24=76.

CS=76−52=24.CS=76-52=24.

Producer's surplus:

PS=x0p0−∫0x0Ps dx=52−∫04(5+2x) dx.PS=x_0p_0-\int_0^{x_0}P_s\,dx=52-\int_0^4(5+2x)\,dx.

∫04(5+2x) dx=[5x+x2]04=20+16=36 ⇒ PS=52−36=16.\int_0^4(5+2x)\,dx=[5x+x^{2}]_0^4=20+16=36\ \Rightarrow\ PS=52-36=16.

(b) X∼N(μ=12, σ=4)X\sim N(\mu=12,\ \sigma=4). Standardise with Z=X−μσZ=\dfrac{X-\mu}{\sigma}. …

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