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Question 12 of 37

Q.Find an equation of the parabolic form y=ax2+bx+cy = ax^2 + bx + c passing through (0,0)(0, 0), (1,1)(1, 1) and (2,20)(2, 20) using Lagranges Interpolation.

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2020Subjective· 2mImportance★★★★★
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Apply Lagrange's formula to (0,0),(1,1),(2,20)(0,0),(1,1),(2,20); the first term is zero, and the rest simplify to y=9x2−8xy = 9x^2 - 8x.

Lagrange's interpolation formula for the points x0=0, x1=1, x2=2x_0=0,\ x_1=1,\ x_2=2 with y0=0, y1=1, y2=20y_0=0,\ y_1=1,\ y_2=20:

y=y0(x−x1)(x−x2)(x0−x1)(x0−x2)+y1(x−x0)(x−x2)(x1−x0)(x1−x2)+y2(x−x0)(x−x1)(x2−x0)(x2−x1).y = y_0\frac{(x-x_1)(x-x_2)}{(x_0-x_1)(x_0-x_2)} + y_1\frac{(x-x_0)(x-x_2)}{(x_1-x_0)(x_1-x_2)} + y_2\frac{(x-x_0)(x-x_1)}{(x_2-x_0)(x_2-x_1)}.

Term 1 (y0=0y_0 = 0): vanishes.

Term 2 (y1=1y_1 = 1):

1⋅(x−0)(x−2)(1−0)(1−2)=x(x−2)(1)(−1)=−(x2−2x)=−x2+2x.1 \cdot \frac{(x-0)(x-2)}{(1-0)(1-2)} = \frac{x(x-2)}{(1)(-1)} = -(x^2 - 2x) = -x^2 + 2x.

Term 3 (y2=20y_2 = 20): …

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