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Worked Examples · Example 14

Q.Using the payoff table of Worked Example 6, with P(S1)=0.3P(S_1)=0.3, P(S2)=0.5P(S_2)=0.5, P(S3)=0.2P(S_3)=0.2, compute the Expected Monetary Value (EMV) of each course of action and state which should be chosen. Also compute the Expected Opportunity Loss (EOL) of each action and verify that it points to the same choice.

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EMV calculation, using the payoff table A1=(200,200,200)A_1=(200,200,200), A2=(100,300,300)A_2=(100,300,300), A3=(50,200,400)A_3=(50,200,400) and probabilities P(S1)=0.3,P(S2)=0.5,P(S3)=0.2P(S_1)=0.3,P(S_2)=0.5,P(S_3)=0.2:

EMV(A1)=200(0.3)+200(0.5)+200(0.2)=60+100+40=200EMV(A_1)=200(0.3)+200(0.5)+200(0.2)=60+100+40=200

EMV(A2)=100(0.3)+300(0.5)+300(0.2)=30+150+60=240EMV(A_2)=100(0.3)+300(0.5)+300(0.2)=30+150+60=240

EMV(A3)=50(0.3)+200(0.5)+400(0.2)=15+100+80=195EMV(A_3)=50(0.3)+200(0.5)+400(0.2)=15+100+80=195

Highest EMV is A2A_2 (240) → choose A2A_2.

EOL calculation, using the regret table from Worked Example 6 — A1=(0,100,200)A_1=(0,100,200), A2=(100,0,100)A_2=(100,0,100), A3=(150,100,0)A_3=(150,100,0) — with the same probabilities:

EOL(A1)=0(0.3)+100(0.5)+200(0.2)=0+50+40=90EOL(A_1)=0(0.3)+100(0.5)+200(0.2)=0+50+40=90

EOL(A2)=100(0.3)+0(0.5)+100(0.2)=30+0+20=50EOL(A_2)=100(0.3)+0(0.5)+100(0.2)=30+0+20=50

EOL(A3)=150(0.3)+100(0.5)+0(0.2)=45+50+0=95EOL(A_3)=150(0.3)+100(0.5)+0(0.2)=45+50+0=95

Lowest EOL is A2A_2 (50) — the same action EMV recommended. …

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