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Question 39 of 41
Q.

The probability function of a random variable is defined as :

X=xX = x−1-1−2-2001122
P(x)P(x)kk2k2k3k3k4k4k5k5k

Then value of k is :

  1. 115\frac{1}{15}
  2. Zero
  3. One
  4. 14\frac{1}{4}
Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2026MCQ· 1mImportance★★★★★
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The total probability must equal 11: 15k=1⇒k=11515k=1\Rightarrow k=\tfrac{1}{15}.

For P(x)P(x) to be a valid probability mass function, all probabilities are non-negative and their sum is 11:

∑P(x)=k+2k+3k+4k+5k=15k.\sum P(x) = k + 2k + 3k + 4k + 5k = 15k.

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