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Numerical Problems · Q9

Q.Calculate Karl Pearson's Coefficient of Correlation between advertising expenditure (X, in ₹'000) and sales (Y, in ₹ lakh) from the following data: X: 2, 4, 6, 8, 10; Y: 3, 6, 7, 10, 14.

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Step 1 — means: Xˉ=2+4+6+8+105=6\bar X = \frac{2+4+6+8+10}{5}=6; Yˉ=3+6+7+10+145=8\bar Y = \frac{3+6+7+10+14}{5}=8.

Step 2 — deviations and products:

XYx=X−6x=X-6y=Y−8y=Y-8xyxyx2x^2y2y^2
23−4−5201625
46−2−2444
670−1001
81022444
101446241636
Total524070

Step 3 — apply the formula:

r=∑xy∑x2⋅∑y2=5240×70=522800=5252.92≈0.98r = \frac{\sum xy}{\sqrt{\sum x^2 \cdot \sum y^2}} = \frac{52}{\sqrt{40\times70}} = \frac{52}{\sqrt{2800}} = \frac{52}{52.92} \approx 0.98 …

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