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Chemistry · Ch 8 — Ionic Equilibrium

Salts of Strong Acid and Strong Base

8.8.1

Salts of Strong Acid and Strong Base

Consider NaOH(aq)+HNO3(aq)→NaNO3(aq)+H2O(l)NaOH(aq)+HNO_3(aq) \rightarrow NaNO_3(aq)+H_2O(l). The salt NaNO3NaNO_3 dissociates completely, NaNO3(aq)→Na+(aq)+NO3−(aq)NaNO_3(aq) \rightarrow Na^+(aq)+NO_3^-(aq). NO3−NO_3^- is the conjugate base of the strong acid HNO3HNO_3 and so has no real tendency to react with H+H^+; Na+Na^+ is the conjugate acid of the strong base NaOHNaOH and has no real tendency to react with OH−OH^-. Since neither ion reacts with water, there is no hydrolysis: [H+]=[OH−][H^+]=[OH^-] (as in pure water) is maintained, and the resulting solution is neutral. …

Misc 8.8.1-exampleWhy NaNO3 gives a neutral solution

Worked out. Both ions of NaNO3NaNO_3 are the conjugate species of a strong parent (the conjugate base of strong HNO3HNO_3, and the conjugate acid of strong NaOHNaOH), and a strong parent's conjugate is always weak -- too weak to pull protons to or from water in any measurable way -- so NaNO3NaNO_3 solution has pH=7pH=7, same as pure w …