CsCl has bcc arrangement, its unit cell edge length is 400pm, its inter atomic distance is (a) 400pm (b) 800pm

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Q. CsCl has bcc arrangement, its unit cell edge length is 400pm, its inter atomic distance is

(a) 400pm

(b) 800pm

(c)

\sqrt{3} \times 100

(d)

\left(\dfrac{\sqrt{3}}{2}\right) \times 400

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Step 1. CsCl adopts a bcc-type arrangement: $Cl^-$ ions at the corners and $Cs^+$ at the body centre (or vice versa), and the two ions touch exactly along the body diagonal of the cube.

Step 2. The full body diagonal of a cube of edge a is $\sqrt{3}\,a$ , and this diagonal spans 4 ionic radii ( $4r = \sqrt{3}a$ ). …

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Q.CsCl has bcc arrangement, its unit cell edge length is 400pm, its inter atomic distance is

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Q.CsCl has bcc arrangement, its unit cell edge length is 400pm, its inter atomic distance is

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