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Mathematics · Ch 4 — Inverse Trigonometric Functions

Graph of the Inverse Tangent Function

4.5.4

Graph of the Inverse Tangent Function

y=tan⁡−1xy=\tan^{-1}x has domain the entire real line and range (−π2,π2)\left(-\tfrac{\pi}2,\tfrac{\pi}2\right). Since tan⁡x\tan x is undefined (has vertical asymptotes) at ±π2\pm\tfrac{\pi}2, the graph of y=tan⁡−1xy=\tan^{-1}x lies STRICTLY between the two horizontal lines y=−π2y=-\tfrac{\pi}2 and y=π2y=\tfrac{\pi}2, approaching but never touching them — these are its two horizontal asymptotes.

Fig. 4.17 shows y=tan⁡xy=\tan x on (−π2,π2)\left(-\tfrac{\pi}2,\tfrac{\pi}2\right), and Fig. 4.18 its reflection in y=xy=x: y=tan⁡−1xy=\tan^{-1}x on (−∞,∞)(-\infty,\infty) — a flattening S-shaped curve through the origin, rising slowly as ∣x∣|x| grows large and hugging its two horizontal asymptotes.

Notes.

(i) tan⁡−1x\tan^{-1}x is strictly increasing and continuous on all of (−∞,∞)(-\infty,\infty). …

Figure 4.17Graph of y = tan x on its principal domain (-pi/2, pi/2): a single strictly increasing branch from minus infinity to plus infinity with vertical asymptotes at x = +/- pi/2.
Fig. 4.17 — Graph of y = tan x on its principal domain (-pi/2, pi/2): a single strictly increasing branch from minus infinity to plus infinity with vertical asymptotes at x = +/- pi/2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. The same single branch of tangent on (−π/2,π/2)\left(-\pi/2,\pi/2\right) shown alongside its inverse to illustrate the reflection. …

Figure 4.18Graph of y = tan^{-1} x on domain (-infinity, infinity): a strictly increasing S-curve through the origin with horizontal asymptotes y = +/- pi/2.
Fig. 4.18 — Graph of y = tan^{-1} x on domain (-infinity, infinity): a strictly increasing S-curve through the origin with horizontal asymptotes y = +/- pi/2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. A flattening S-curve through the origin that rises from just above −π/2-\pi/2 to just below π/2\pi/2, hugging two dashed horizontal asymptote lines y=−π/2y=-\pi/2 and y=π/2y=\pi/2 without ever touching them. …