Skip to content
Exercise 4.5 · Q2

Q.Find the value of the expression in terms of xx, with the help of a reference triangle.

(i) sin⁡(cos⁡−1(1−x))\sin\left(\cos^{-1}(1-x)\right)
(ii) cos⁡(tan⁡−1(3x−1))\cos\left(\tan^{-1}(3x-1)\right)
(iii) tan⁡(sin⁡−1(x+12))\tan\left(\sin^{-1}\left(x+\dfrac12\right)\right).
Puducherry TnboardTextbookSubjectiveImportance★★★★★
32% · 23/71 Questions
✓ Free question

Each expression names an angle via one inverse-trig ratio, builds the other two sides by Pythagoras (always taking the positive root, matching the principal range's sign), and reads off the requested ratio.

Step 1. (i) Name the angle. Let θ=cos⁡−1(1−x)\theta=\cos^{-1}(1-x), so cos⁡θ=1−x\cos\theta=1-x, θ∈[0,π]\theta\in[0,\pi], hence sin⁡θ≥0\sin\theta\ge0.

Step 2. (i) Find sin⁡θ\sin\theta. sin⁡θ=1−cos⁡2θ=1−(1−x)2=1−(1−2x+x2)=2x−x2\sin\theta=\sqrt{1-\cos^2\theta}=\sqrt{1-(1-x)^2}=\sqrt{1-(1-2x+x^2)}=\sqrt{2x-x^2}.

Step 3. (ii) Name the angle. Let θ=tan⁡−1(3x−1)\theta=\tan^{-1}(3x-1), so tan⁡θ=3x−1\tan\theta=3x-1, θ∈(−π2,π2)\theta\in\left(-\dfrac{\pi}2,\dfrac{\pi}2\right), hence cos⁡θ>0\cos\theta>0.

Step 4. (ii) Find cos⁡θ\cos\theta via the reference triangle (opposite =3x−1=3x-1, adjacent =1=1, hypotenuse =1+(3x−1)2=\sqrt{1+(3x-1)^2}). cos⁡θ=11+(3x−1)2=19x2−6x+2\cos\theta=\dfrac1{\sqrt{1+(3x-1)^2}}=\dfrac1{\sqrt{9x^2-6x+2}}.

Step 5. (iii) Name the angle. Let θ=sin⁡−1(x+12)\theta=\sin^{-1}\left(x+\dfrac12\right), so sin⁡θ=x+12\sin\theta=x+\dfrac12, θ∈[−π2,π2]\theta\in\left[-\dfrac{\pi}2,\dfrac{\pi}2\right], hence cos⁡θ≥0\cos\theta\ge0.

Step 6. (iii) Find cos⁡θ\cos\theta and hence tan⁡θ\tan\theta. cos⁡θ=1−(x+12)2\cos\theta=\sqrt{1-\left(x+\dfrac12\right)^2}, so tan⁡θ=sin⁡θcos⁡θ=x+121−(x+12)2\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{x+\frac12}{\sqrt{1-\left(x+\frac12\right)^2}}.

✓Final answer

(i) 2x−x2\sqrt{2x-x^2}. (ii) 19x2−6x+2\dfrac1{\sqrt{9x^2-6x+2}}. (iii) x+121−(x+12)2\dfrac{x+\frac12}{\sqrt{1-\left(x+\frac12\right)^2}}.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.