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Exercise 10.4 · Q3

Q.The slope of the tangent to the curve at any point is the reciprocal of four times the ordinate at that point. The curve passes through (2,5)(2,5). Find the equation of the curve.

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✓ Free question

"Slope is the reciprocal of four times the ordinate" translates directly to dydx=14y\dfrac{dy}{dx}=\dfrac{1}{4y}, a separable equation; integrate and use the given point to find the particular solution.

Step 1. Set up the differential equation. dydx=14y\dfrac{dy}{dx}=\dfrac{1}{4y}.

Step 2. Separate variables. 4y dy=dx4y\,dy=dx.

Step 3. Integrate both sides. 2y2=x+C2y^2=x+C.

Step 4. Apply the point (2,5)(2,5). 2(5)2=2+C ⟹ 50=2+C ⟹ C=482(5)^2=2+C\ \Longrightarrow\ 50=2+C\ \Longrightarrow\ C=48.

Step 5. State the curve. 2y2=x+482y^2=x+48.

✓Final answer

2y2=x+482y^2=x+48

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