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Exercise 10.9 · Q2

Q.The differential equation representing the family of curves y=Acos⁡(x+B)y=\mathrm{A}\cos(x+\mathrm{B}), where A\mathrm{A} and B\mathrm{B} are parameters, is

(1) d2ydx2−y=0\dfrac{d^2y}{dx^2}-y=0
(2) d2ydx2+y=0\dfrac{d^2y}{dx^2}+y=0
(3) d2ydx2=0\dfrac{d^2y}{dx^2}=0
(4) d2xdy2=0\dfrac{d^2x}{dy^2}=0
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✓ Free question

Differentiate twice; the phase shift B\mathrm B inside the cosine does not survive differentiation as a separate term (it is absorbed inside the trig function throughout).

Step 1. Differentiate once. y=Acos⁡(x+B) ⟹ y′=−Asin⁡(x+B)y=\mathrm A\cos(x+\mathrm B)\ \Longrightarrow\ y'=-\mathrm A\sin(x+\mathrm B).

Step 2. Differentiate again. y′′=−Acos⁡(x+B)=−yy''=-\mathrm A\cos(x+\mathrm B)=-y.

Step 3. State the equation. y′′+y=0y''+y=0.

✓Final answer

Option (2): d2ydx2+y=0\dfrac{d^2y}{dx^2}+y=0.

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