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Exercise 5.5 · Q10

Q.Points AA and BB are 10 km10\,\text{km} apart and it is determined from the sound of an explosion heard at those points at different times that the location of the explosion is 6 km6\,\text{km} closer to AA than BB. Show that the location of the explosion is restricted to a particular curve and find an equation of it.

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'6 km closer to A than B' is exactly the constant-difference-of-focal-distances defining property of a hyperbola with foci A,BA,B — so no new derivation is needed beyond identifying a,c,ba,c,b.

Step 1. Recognise the defining property. ∣PB−PA∣=6|PB-PA|=6 for every possible explosion location PP — this constant-difference-from-two-fixed-points condition is precisely the focus-pair definition of a hyperbola, with A,BA,B as the two foci.

Step 2. Identify aa and cc.

2a=6⇒a=32a=6\Rightarrow a=3 (constant difference == transverse axis length).

2c=AB=10⇒c=52c=AB=10\Rightarrow c=5 (distance between foci).

Step 3. Find b2b^2.

b2=c2−a2=25−9=16b^2=c^2-a^2=25-9=16. …

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