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Question 116 of 126

Q.If P(x,y)P(x, y) be any point on 16x2+25y2=40016x^2+25y^2=400 with foci F1(3,0)F_1(3, 0) and F2(−3,0)F_2(-3, 0), then PF1+PF2PF_1+PF_2 is :

(a) 1010
(b) 88
(c) 1212
(d) 66
Puducherry TnboardTamil Nadu HSC (DGE) Board 2024MCQ· 1mImportance★★★★★
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Converts to standard ellipse form to read off aa, then applies the defining focal-distance property PF1+PF2=2aPF_1+PF_2=2a.

  1. Divide 16x2+25y2=40016x^2+25y^2=400 by 400400: x225+y216=1\dfrac{x^2}{25}+\dfrac{y^2}{16}=1.
  2. So a2=25⇒a=5a^2=25\Rightarrow a=5 (since 25>1625>16, the major axis is along xx, matching foci on the xx-axis at (±3,0)(\pm3,0)). …

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