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Physics · Ch 6 — Optics

Relation Between f and R

6.2.2

Relation Between f and R

For a concave mirror, a paraxial ray parallel to the principal axis strikes the mirror at MM and reflects through the principal focus FF; the line CMCM (through the centre of curvature) is the normal at MM, and the angle of incidence there equals the angle of reflection, both denoted ii. Dropping the perpendicular MPMP from MM onto the axis, the right triangles △MCP\triangle MCP and △MFP\triangle MFP give tan⁡i=PM/PC\tan i = PM/PC and tan⁡2i=PM/PF\tan 2i = PM/PF (using the exterior-angle property that ∠MFP=2i\angle MFP=2i). For paraxial rays, tan⁡i≈i\tan i\approx i and tan⁡2i≈2i\tan 2i\approx 2i, so i=PM/PCi=PM/PC and 2i=PM/PF2i=PM/PF; dividing these two relations gives PF=PC/2PF=PC/2, i.e. f=R/2\boxed{f=R/2}. The identical construction, wo …

Figure 6.9Relation between R and f

What this figure shows. A ray parallel to the principal axis strikes a concave mirror at M, with CM as the normal (since it passes through the centre of curvature C) making angle i with the incident ray, and the reflected ray crossing the axis at the focus F making angle 2i with CM by the exterior-angle property of triangle MCF. Dropping a perpendicular MP to the axis and applying the small-angle approximation to the two right triangles MCP and MFP gives PF = PC/2, i.e. f = R/2; a companion diagram (b) shows the identical construction carried out f …