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Problems · Problem 6.13

Q.Write the conjugate acids for the following Brönsted bases: NH2 –, NH3 and HCOO–.

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The conjugate acid of a Brønsted base is formed by adding one proton (H+\text{H}^+) to the base. For NH2−\text{NH}_2^-, the conjugate acid is NH3\text{NH}_3; for NH3\text{NH}_3, it is NH4+\text{NH}_4^+; for HCOO−\text{HCOO}^-, it is HCOOH\text{HCOOH}.

The Core Idea: Conjugate Pairs

The Brønsted-Lowry theory defines an acid as a proton (H+\text{H}^+) donor and a base as a proton acceptor. Every base has a conjugate acid — the species formed after the base accepts a proton. The relationship is simple:

Base+H+→Conjugate Acid\text{Base} + \text{H}^+ \rightarrow \text{Conjugate Acid}

So to find the conjugate acid of any base, you literally add one H+\text{H}^+ to its formula. The charge also adjusts: adding a positive proton increases the charge by +1.

Let’s apply this to each base.


1. Base: NH2−\text{NH}_2^- (amide ion)

Add one H+\text{H}^+ to NH2−\text{NH}_2^-:

  • The nitrogen already has two hydrogens; adding a third gives NH3\text{NH}_3.
  • Charge: −1+(+1)=0-1 + (+1) = 0.

So the conjugate acid is ammonia, NH3\text{NH}_3.

Tip

Notice that NH3\text{NH}_3 itself is a base in water, but here it acts as the conjugate acid of the amide ion. This is a classic example of an amphoteric species — ammonia can both accept and donate a proton depending on the partner.


2. Base: NH3\text{NH}_3 (ammonia)

Add one H+\text{H}^+ to NH3\text{NH}_3:

  • The nitrogen has a lone pair that can accept a proton, forming NH4+\text{NH}_4^+.
  • Charge: 0+(+1)=+10 + (+1) = +1.

So the conjugate acid is the ammonium ion, NH4+\text{NH}_4^+. …

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