Q.If 0.561 g of KOH is dissolved in water to give 200 mL of solution at 298 K. Calculate the concentrations of potassium, hydrogen and hydroxyl ions. What is its pH?
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Start your 14-day free trial to unlock the full solution →Dissolving KOH in water produces a strong base that dissociates completely. The concentration of is found from molarity, then follows from , and pH from . Final answer: , , pH .
Potassium hydroxide is a strong base, meaning it dissociates completely in water. When KOH dissolves, every formula unit splits into one potassium ion and one hydroxide ion:
Because the dissociation is complete, the concentration of equals the concentration of , and both equal the molarity of the KOH solution. Once we know , we can find using the water equilibrium constant at 298 K. The pH then follows directly from the hydrogen ion concentration.
Step-by-step calculation
1. Find the number of moles of KOH
The molar mass of KOH is:
Number of moles:
2. Calculate the molarity of the KOH solution
Volume in litres is .
3. Determine the concentration of potassium and hydroxyl ions
Since KOH dissociates completely:
4. Calculate the hydrogen ion concentration
Using the ionic product of water at 298 K:
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