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Exercises · 8.37

Q.In the Lassaigne's test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na4[Fe(CN)6]
(b) Fe4[Fe(CN)6]3
(c) Fe2[Fe(CN)6]
(d) Fe3[Fe(CN)6]4.
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The Prussian blue colour in Lassaigne’s test comes from the formation of ferric ferrocyanide, Fe4[Fe(CN)6]3\text{Fe}_4[\text{Fe}(\text{CN})_6]_3, which is option (b). The test works by converting nitrogen in the organic compound to cyanide ion, then to ferrocyanide, and finally reacting with ferric ion to give the deep blue complex.

Why Lassaigne’s test works — the chemistry behind the colour

When you fuse an organic compound with sodium metal, any nitrogen present is converted into sodium cyanide (NaCN). This is the key first step — the sodium breaks the organic molecule and “captures” the nitrogen as cyanide ion.

But cyanide ion alone doesn’t give a coloured product with iron salts in a useful way. The test relies on a clever sequence: you first convert the cyanide into ferrocyanide ion, [Fe(CN)6]4−[\text{Fe}(\text{CN})_6]^{4-}, by adding ferrous sulphate. Then, when you add ferric chloride, the ferric ion (Fe3+\text{Fe}^{3+}) reacts with ferrocyanide to form an intensely blue precipitate — Prussian blue.

The exact composition of Prussian blue has been debated historically, but the formula accepted in standard textbooks (and in exam contexts) is Fe4[Fe(CN)6]3\text{Fe}_4[\text{Fe}(\text{CN})_6]_3. Let’s see why.

Step-by-step reasoning

  1. Fusion with sodium The organic compound (containing N) is heated with Na metal.

Organic-N+Na→ΔNaCN\text{Organic-N} + \text{Na} \xrightarrow{\Delta} \text{NaCN}

This sodium cyanide dissolves in water when the fused mass is extracted.

  1. Formation of sodium ferrocyanide Freshly prepared ferrous sulphate is added to the extract. The Fe2+\text{Fe}^{2+} ions react with CN⁻ to first form Fe(CN)2\text{Fe}(\text{CN})_2, which then reacts with excess CN⁻ to give the ferrocyanide complex:

Fe2++6CN−→[Fe(CN)6]4−\text{Fe}^{2+} + 6\text{CN}^- \rightarrow [\text{Fe}(\text{CN})_6]^{4-}

The sodium salt, Na4[Fe(CN)6]\text{Na}_4[\text{Fe}(\text{CN})_6], is formed in solution.

  1. Boiling to oxidise iron

    The solution is boiled. This step is crucial — it oxidises any leftover Fe2+\text{Fe}^{2+} to Fe3+\text{Fe}^{3+}, and also ensures that the ferrocyanide is fully formed. If you skip boiling, you might get a greenish colour instead of blue.

  2. Addition of ferric chloride

    Now you add FeCl3\text{FeCl}_3. The Fe3+\text{Fe}^{3+} ions react with the ferrocyanide ion:

4Fe3++3[Fe(CN)6]4−→Fe4[Fe(CN)6]34\text{Fe}^{3+} + 3[\text{Fe}(\text{CN})_6]^{4-} \rightarrow \text{Fe}_4[\text{Fe}(\text{CN})_6]_3

This is Prussian blue — an insoluble, deep blue complex. …

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