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Problems · Problem 7.4

Q.Justify that the reaction: 2Cu2O(s) + Cu2S(s) → 6Cu(s) + SO2(g) is a redox reaction. Identify the species oxidised/reduced, which acts as an oxidant and which acts as a reductant.

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This reaction is redox because the oxidation states of copper and sulphur both change — copper is reduced (from +1 to 0) and sulphur is oxidised (from –2 to +4). Copper(I) — present in both Cu₂O and Cu₂S — is the oxidant; the sulphur of Cu₂S is the reductant.

Why this is a redox reaction — the core idea

A reaction is redox if there is a transfer of electrons, which shows up as a change in oxidation states. Here, we have two copper compounds reacting to give pure copper metal and sulphur dioxide. The copper ends up in a lower oxidation state (it gains electrons), while the sulphur ends up in a higher oxidation state (it loses electrons). That simultaneous gain and loss of electrons is the hallmark of a redox reaction.

Let’s assign oxidation states to every atom in the reaction:

2Cu2O(s)+Cu2S(s)→6Cu(s)+SO2(g)2\text{Cu}_2\text{O}(s) + \text{Cu}_2\text{S}(s) \rightarrow 6\text{Cu}(s) + \text{SO}_2(g)

  1. Oxidation state of copper in Cu₂O

    Oxygen is always –2 (except in peroxides). In Cu₂O, the total charge is 0.

    Let Cu be xx. Then 2x+(−2)=0⇒2x=+2⇒x=+12x + (-2) = 0 \Rightarrow 2x = +2 \Rightarrow x = +1.

    So each Cu in Cu₂O is +1.

  2. Oxidation state of copper in Cu₂S

    Sulphur in sulphides is usually –2. Let Cu be yy. Then 2y+(−2)=0⇒y=+12y + (-2) = 0 \Rightarrow y = +1.

    So each Cu in Cu₂S is also +1.

  3. Oxidation state of copper in the product

    Pure Cu metal has oxidation state 0.

  4. Oxidation state of sulphur in Cu₂S

    As above, S is –2.

  5. Oxidation state of sulphur in SO₂

    Oxygen is –2. Let S be zz. Then z+2(−2)=0⇒z−4=0⇒z=+4z + 2(-2) = 0 \Rightarrow z - 4 = 0 \Rightarrow z = +4.

    So S in SO₂ is +4.

Now we can see the changes:

SpeciesInitial O.S.Final O.S.ChangeWhat happens
Cu (from Cu₂O)+10–1 (gain of 1 e⁻)Reduction
Cu (from Cu₂S)+10–1 (gain of 1 e⁻)Reduction
S (from Cu₂S)–2+4+6 (loss of 6 e⁻)Oxidation
Watch out

A common mistake is to think that because copper appears in two different reactants, it must be undergoing two different changes. But here, all copper atoms start at +1 and end at 0 — they are all reduced. The only atom that gets oxidised is sulphur.

Identifying the oxidant and reductant …

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