Q.Justify that the reaction: 2Cu2O(s) + Cu2S(s) → 6Cu(s) + SO2(g) is a redox reaction. Identify the species oxidised/reduced, which acts as an oxidant and which acts as a reductant.
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Start your 14-day free trial to unlock the full solution →This reaction is redox because the oxidation states of copper and sulphur both change — copper is reduced (from +1 to 0) and sulphur is oxidised (from –2 to +4). Copper(I) — present in both Cu₂O and Cu₂S — is the oxidant; the sulphur of Cu₂S is the reductant.
Why this is a redox reaction — the core idea
A reaction is redox if there is a transfer of electrons, which shows up as a change in oxidation states. Here, we have two copper compounds reacting to give pure copper metal and sulphur dioxide. The copper ends up in a lower oxidation state (it gains electrons), while the sulphur ends up in a higher oxidation state (it loses electrons). That simultaneous gain and loss of electrons is the hallmark of a redox reaction.
Let’s assign oxidation states to every atom in the reaction:
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Oxidation state of copper in Cu₂O
Oxygen is always –2 (except in peroxides). In Cu₂O, the total charge is 0.
Let Cu be . Then .
So each Cu in Cu₂O is +1.
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Oxidation state of copper in Cu₂S
Sulphur in sulphides is usually –2. Let Cu be . Then .
So each Cu in Cu₂S is also +1.
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Oxidation state of copper in the product
Pure Cu metal has oxidation state 0.
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Oxidation state of sulphur in Cu₂S
As above, S is –2.
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Oxidation state of sulphur in SO₂
Oxygen is –2. Let S be . Then .
So S in SO₂ is +4.
Now we can see the changes:
| Species | Initial O.S. | Final O.S. | Change | What happens |
|---|---|---|---|---|
| Cu (from Cu₂O) | +1 | 0 | –1 (gain of 1 e⁻) | Reduction |
| Cu (from Cu₂S) | +1 | 0 | –1 (gain of 1 e⁻) | Reduction |
| S (from Cu₂S) | –2 | +4 | +6 (loss of 6 e⁻) | Oxidation |
A common mistake is to think that because copper appears in two different reactants, it must be undergoing two different changes. But here, all copper atoms start at +1 and end at 0 — they are all reduced. The only atom that gets oxidised is sulphur.
Identifying the oxidant and reductant …
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