Q.Identify the correct statement (s) in relation to the following reaction:
Zn + 2HCl → ZnCl2 + H2 (Note: more than one of the given options may be correct.)
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Start your 14-day free trial to unlock the full solution →In the reaction , zinc loses electrons (oxidation) and acts as a reductant, while hydrogen ions gain electrons (reduction) and act as an oxidant. The correct statements are (iii) and (iv).
This is a classic single-displacement redox reaction. The key is to track the transfer of electrons — who loses them and who gains them. Oxidation is loss, reduction is gain. The substance that gets oxidised (loses electrons) is the reductant (reducing agent), because it causes reduction by giving electrons to something else. The substance that gets reduced (gains electrons) is the oxidant (oxidising agent), because it causes oxidation by taking electrons.
Let’s break it down step by step.
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Assign oxidation states to track the change.
On the left: Zn is in its elemental form, so its oxidation state is 0. H in HCl is +1, Cl is -1.
On the right: In , Zn is +2 (since Cl is -1, and the compound is neutral). H in is 0 (elemental form). Cl remains -1 throughout.
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Identify what happens to each element.
- Zinc: goes from 0 to +2. It loses two electrons. That’s oxidation.
- Hydrogen: goes from +1 to 0. It gains one electron per atom (two total). That’s reduction.
- Chlorine: stays at -1. No change — it is a spectator ion here, not involved in the redox.
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Name the roles.
Since zinc is oxidised, it is the reductant (reducing agent). It donates electrons to the hydrogen ions.
Since hydrogen ions are reduced, they are the oxidant (oxidising agent). They accept electrons from zinc.
Chlorine does nothing redox-wise, so it is neither an oxidant nor a reductant in this reaction. …
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