Q.Two litres of an ideal gas at a pressure of 10 atm expands isothermally at 25 °C into a vacuum until its total volume is 10 litres. How much heat is absorbed and how much work is done in the expansion?
For an isothermal free expansion into vacuum, no work is done () and no heat is exchanged () because the gas does not push against any external pressure and the internal energy of an ideal gas depends only on temperature.
The question describes a classic scenario: an ideal gas expanding into a vacuum. The key is to recognise that "expands into a vacuum" means the external pressure is zero. This is a free expansion.
Let’s start with the First Law of Thermodynamics:
Here, is heat absorbed by the system, is work done on the system (many textbooks use as work done by the system, so the sign convention matters — we’ll stick with the physics convention where is work done on the gas; if work is done by the gas, is negative).
For an ideal gas, internal energy depends only on temperature. Since the process is isothermal (temperature constant at 25 °C), the change in internal energy is zero:
Now, work done during expansion against an external pressure is:
The negative sign appears because when the gas expands (), work is done by the gas, so work done on the gas is negative.
In a free expansion into vacuum, . Therefore:
From the First Law:
So no heat is absorbed and no work is done.
A common mistake is to try to calculate work using for an isothermal process. That formula applies only when the expansion is reversible — i.e., when the external pressure is infinitesimally less than the gas pressure at every step. In a free expansion, the external pressure is zero throughout, so no work is done. The reversible formula gives the maximum work possible, not the actual work here.
Think of it this way: if you push against a wall that isn’t there, you do no work. The gas expands into empty space — there’s nothing to push against. So no energy is transferred as work, and since temperature doesn’t change, no heat flows either.
The heat absorbed is and the work done is .
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