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Worked Examples · Example 1

Q.Find the mean deviation about the mean for the following data: 6, 7, 10, 12, 13, 4, 8, 12

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✓ Free question

The mean of the data is 99, and the mean deviation about the mean is 2.752.75.

Understanding Mean Deviation About the Mean

Mean deviation measures how far, on average, each observation lies from the arithmetic mean. It uses absolute values (not squares), so it directly answers "how far is a typical data point from the centre?"

M.D.(xˉ)=∑∣xi−xˉ∣n\text{M.D.}(\bar{x}) = \frac{\sum |x_i - \bar{x}|}{n}

where xˉ\bar{x} is the mean and nn is the number of observations.

Step-by-Step Solution

1. Find the mean

∑xi=6+7+10+12+13+4+8+12=72,n=8\sum x_i = 6 + 7 + 10 + 12 + 13 + 4 + 8 + 12 = 72, \qquad n = 8

xˉ=728=9\bar{x} = \frac{72}{8} = 9

2. Absolute deviations from the mean

| xix_i | ∣xi−9∣|x_i - 9| |

|-------|-------------|

| 6 | 3 |

| 7 | 2 |

| 10 | 1 |

| 12 | 3 |

| 13 | 4 |

| 4 | 5 |

| 8 | 1 |

| 12 | 3 |

3. Sum the absolute deviations

∑∣xi−xˉ∣=3+2+1+3+4+5+1+3=22\sum |x_i - \bar{x}| = 3 + 2 + 1 + 3 + 4 + 5 + 1 + 3 = 22

4. Divide by nn

M.D.(xˉ)=228=2.75\text{M.D.}(\bar{x}) = \frac{22}{8} = 2.75

✓Final answer

The mean deviation about the mean is 2.752.75.

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