Skip to content
Exercises · 12.8

Q.Three vessels of equal capacity have gases at the same temperature and pressure. The first vessel contains neon (monatomic), the second contains chlorine (diatomic), and the third contains uranium hexafluoride (polyatomic). Do the vessels contain equal number of respective molecules? Is the root mean square speed of molecules the same in the three cases? If not, in which case is vrmsv_{rms} the largest?

Punjab PsebTextbookSubjective· 3mImportance★★★★★est
34% · 17/50 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

By the ideal gas law at equal PP, VV, and TT, all three vessels contain the same number of molecules. However, vrmsv_{\text{rms}} depends inversely on M\sqrt{M}, so the lightest gas (neon) has the largest root mean square speed.

The question probes two fundamental ideas from kinetic theory: how the number of molecules relates to macroscopic state variables, and how molecular mass governs thermal speeds.

Equal number of molecules?

The ideal gas law connects the macroscopic state to the microscopic count:

PV=nRT=NkTPV = nRT = NkT

where nn is the number of moles, NN is the number of molecules, RR is the universal gas constant, and kk is Boltzmann's constant. Rearranging for the number of molecules:

N=PVkTN = \frac{PV}{kT}

Since all three vessels have the same pressure PP, volume VV (equal capacity), and temperature TT, the right-hand side is identical for all three. The chemical identity of the gas—whether monatomic neon, diatomic chlorine, or polyatomic uranium hexafluoride—does not appear in this relation.

The vessels contain equal numbers of molecules. This is Avogadro's principle: equal volumes of gases at the same temperature and pressure contain equal numbers of molecules, regardless of the gas species.

Note

The atomicity (mono-, di-, or polyatomic) affects properties like specific heat capacity and internal energy distribution, but not the molecule count at given PP, VV, TT.

Root mean square speed

The root mean square speed emerges from the kinetic interpretation of temperature. For an ideal gas, the average translational kinetic energy per molecule is:

12m⟨v2⟩=32kT\frac{1}{2}m\langle v^2 \rangle = \frac{3}{2}kT

where mm is the mass of one molecule and ⟨v2⟩\langle v^2 \rangle is the mean square speed. Solving for vrms=⟨v2⟩v_{\text{rms}} = \sqrt{\langle v^2 \rangle}:

vrms=3kTm=3RTMv_{\text{rms}} = \sqrt{\frac{3kT}{m}} = \sqrt{\frac{3RT}{M}}

where MM is the molar mass. The second form uses k=R/NAk = R/N_A and m=M/NAm = M/N_A.

At the same temperature, vrmsv_{\text{rms}} is inversely proportional to M\sqrt{M}. The three gases have very different molar masses:

| Gas | Formula | Molar mass (g/mol) |

|-----|---------|-------------------| …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.