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Worked Examples · Example 14.3

Q.A steel wire 0.72 m0.72\ \text{m} long has a mass of 5.0×10−3 kg5.0 \times 10^{-3}\ \text{kg}. If the wire is under a tension of 60 N60\ \text{N}, what is the speed of transverse waves on the wire?

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Using v=T/μv=\sqrt{T/\mu} with the wire's linear mass density μ=m/L\mu=m/L, the speed of transverse waves on the steel wire is v≈93 m/sv\approx\boxed{93\ \text{m/s}}.

The governing formula

The speed of a transverse wave on a stretched wire depends on the tension TT and its linear mass density μ\mu:

v=Tμv = \sqrt{\frac{T}{\mu}}

Step-by-step calculation

1. Find the linear mass density.

μ=mL=5.0×10−30.72≈6.944×10−3 kg/m\mu = \frac mL = \frac{5.0\times10^{-3}}{0.72} \approx 6.944\times10^{-3}\ \text{kg/m}

2. Identify the tension.

T=60 NT=60\ \text{N}.

3. Apply the wave speed formula.

v=Tμ=606.944×10−3=8640.6≈92.95 m/s≈93 m/sv = \sqrt{\frac T\mu} = \sqrt{\frac{60}{6.944\times10^{-3}}} = \sqrt{8640.6} \approx 92.95\ \text{m/s} \approx 93\ \text{m/s} …

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