Q.Write the output on execution of the following Python code: S="Racecar Car Radar" L=S.split() for W in L: x=W.upper() if x==x[::-1]: for I in x: print(I,end="*") else: for I in W: print(I,end="#") print()

Concept: String manipulation with palindrome checking and conditional output formatting.

The code splits the string into words, then for each word checks whether its uppercase version is a palindrome (reads the same forwards and backwards). If palindromic, it prints each character of the uppercase word followed by *; otherwise, it prints each character of the original word followed by #.

Step-by-step execution:

1. S.split() gives L = ["Racecar", "Car", "Radar"]
2. For "Racecar": uppercase is "RACECAR", which equals "RACECAR"[::-1] (palindrome) → print each letter of "RACECAR" with *: R*A*C*E*C*A*R* then newline …

Concept: String manipulation and palindrome detection

The code demonstrates three core Python ideas working together: string splitting, palindrome checking via slice reversal, and conditional character-by-character output. A palindrome reads the same forwards and backwards; the slice [::-1] reverses a string, so comparing x == x[::-1] tests this property. The key insight is that the palindrome check uses the uppercase version but the output format depends on whether that check passes.

Let's trace through the execution step by step.

Execution trace

1. Initialization: S = "Racecar Car Radar" and L = S.split() produces the list L = ["Racecar", "Car", "Radar"].

2. First iteration (W = "Racecar"):

   • Convert to uppercase: x = "RACECAR"
   • Check palindrome: "RACECAR" == "RACECAR"[::-1] → "RACECAR" == "RACECAR" → True
   • Since it's a palindrome, loop through each character in x and print with *:

     R*A*C*E*C*A*R*
     

   • The print() at the end adds a newline.

3. Second iteration (W = "Car"):

   • Convert to uppercase: x = "CAR"
   • Check palindrome: "CAR" == "RAC" → False
   • Since it's not a palindrome, loop through each character in W (original case) and print with #:

     C#a#r#
     ``` …