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NCERT Exemplar · Q36

Q.Which of the following complexes are homoleptic?

(i) [Co(NH3)6]3+[Co(NH_3)_6]^{3+}
(ii) [Co(NH3)4Cl2]+[Co(NH_3)_4Cl_2]^{+}
(iii) [Ni(CN)4]2−[Ni(CN)_4]^{2-}
(iv) [Ni(NH3)4Cl2][Ni(NH_3)_4Cl_2]
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Homoleptic complexes contain only one type of ligand. Among the given options, (i) [Co(NH3)6]3+[Co(NH_3)_6]^{3+} and (iii) [Ni(CN)4]2−[Ni(CN)_4]^{2-} are homoleptic; (ii) and (iv) have two different ligands and are heteroleptic.

The term homoleptic comes from Greek roots: homo (same) and leptos (taken/held). In coordination chemistry, a homoleptic complex is one where the metal ion is bound to only one kind of ligand. If even two different types of ligands are present, the complex is heteroleptic.

This is a classification based purely on ligand identity — not on charge, geometry, or oxidation state. So the task is simply to check each complex: does it contain only one type of ligand, or more than one?

Let’s examine each option.

  1. Option (i): [Co(NH3)6]3+[Co(NH_3)_6]^{3+}

    The only ligand here is ammonia (NH3NH_3). All six coordination sites are occupied by the same ligand.

    → Homoleptic.

  2. Option (ii): [Co(NH3)4Cl2]+[Co(NH_3)_4Cl_2]^{+}

    Two different ligands are present: ammonia (NH3NH_3) and chloride (Cl−Cl^-). Four sites have NH3NH_3, two have Cl−Cl^-.

    → Heteroleptic.

  3. Option (iii): [Ni(CN)4]2−[Ni(CN)_4]^{2-}

    The only ligand is cyanide (CN−CN^-). All four coordination sites are identical in ligand type.

    → Homoleptic.

  4. Option (iv): [Ni(NH3)4Cl2][Ni(NH_3)_4Cl_2]

    Again, two different ligands: ammonia and chloride. Even though the complex is neutral, the ligand set is mixed. …

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