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Q.(a) When HgI2 is added to aqueous solution of KI, why there is an increase in osmotic pressure of solution ?

(b) Commercially available HCl contains 38% HCl by mass. Calculate molality of the solution.
Punjab PsebPSEB Punjab Class 12 Board 2018Subjective· 4mImportance★★★★★
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(a) HgI₂ becomes a soluble, fully dissociating complex salt in KI solution, raising the total particle count and hence the osmotic pressure. (b) 38% HCl by mass works out to about 16.8 mol of HCl per kg of water.

(a) Increase in osmotic pressure:

Mercuric iodide, HgI2HgI_2, is essentially insoluble in water on its own. But in the presence of excess iodide ions (from KI), it dissolves by forming a soluble complex ion, the tetraiodomercurate(II) ion:

HgI2+2KI→K2[HgI4]HgI_2 + 2KI \rightarrow K_2[HgI_4]

This salt dissociates completely in water:

K2[HgI4]→2K++[HgI4]2−K_2[HgI_4] \rightarrow 2K^+ + [HgI_4]^{2-}

Since osmotic pressure (π=iCRT\pi = iCRT) depends on the total number of solute particles in solution, converting the previously undissolved HgI2HgI_2 into freely dissolved, dissociated ionic species genuinely increases the number of particles present — so the osmotic pressure of the solution rises above what would be expected from KI alone.

(b) Molality of 38% HCl by mass:

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