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Intext Questions · 4.1

Q.Silver atom has completely filled d orbitals (4d104d^{10}) in its ground state. How can you say that it is a transition element?

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Silver’s ground-state configuration is [Kr] 4d105s1[Kr]\,4d^{10}5s^1. Although the 4d4d subshell is fully filled, silver is a transition element because in its common +1 oxidation state it loses the 5s5s electron, leaving a 4d104d^{10} configuration — but the definition of a transition element hinges on having an incomplete dd subshell either in the ground state or in any common oxidation state. Silver qualifies because it can form Ag2+Ag^{2+} (with 4d94d^9), which is an incomplete dd subshell. The key is that the definition does not require the ground state itself to have an incomplete dd subshell.

Why This Question Trips Students Up

The confusion is natural. You see 4d104d^{10} — a completely filled dd subshell — and think “that’s not a transition element.” But the official IUPAC definition (and the one used in Indian board exams) is broader:

Transition element: An element whose atom has an incomplete dd subshell or which can give rise to cations with an incomplete dd subshell.

This means we must check both the ground state and the common oxidation states of the element. Silver’s ground state is 4d105s14d^{10}5s^1 — the dd subshell is full. But that’s not the end of the story.

Step-by-Step Reasoning

  1. Write the ground-state electronic configuration of silver (Ag, atomic number 47).

    Following the Aufbau principle:

    1s22s22p63s23p63d104s24p64d105s11s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10} 5s^1

    In condensed form: [Kr] 4d105s1[Kr]\,4d^{10}5s^1.

    The 4d4d subshell is completely filled — no doubt about that.

  2. Check the ground state against the definition.

    The ground state has 4d104d^{10} — a full dd subshell. So by the first part of the definition (incomplete dd subshell in the atom), silver does not qualify.

    But the definition has a second part: “or which can give rise to cations with an incomplete dd subshell.”

  3. Examine the common oxidation states of silver.

    Silver most commonly forms Ag+Ag^+ (as in AgNO3AgNO_3, AgClAgCl, etc.).

    Ag+Ag^+: remove the 5s15s^1 electron → configuration becomes [Kr] 4d10[Kr]\,4d^{10}.

    That’s still a full d10d^{10} — so Ag+Ag^+ does not have an incomplete dd subshell either.

    At this point, many students stop and conclude silver is not a transition element. But that’s a mistake — because we haven’t checked all common oxidation states.

  4. Look for a less common but still important oxidation state: Ag2+Ag^{2+}.

    Silver can also form Ag2+Ag^{2+} compounds (e.g., AgF2AgF_2, AgOAgO). This is a stable oxidation state, though less common than +1+1.

    Ag2+Ag^{2+}: remove the 5s15s^1 electron and one 4d4d electron → configuration becomes [Kr] 4d9[Kr]\,4d^9.

    4d94d^9 is incomplete — it has one vacancy in the dd subshell. …

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