Q.Differentiate , w.r.t. .
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Start your 14-day free trial to unlock the full solution →We differentiate by rewriting it as and then applying the chain rule and product rule. The derivative is .
The function is not a simple power function (where the exponent is constant) nor a simple exponential (where the base is constant). The variable appears in both the base and the exponent. To handle this, we use a technique called logarithmic differentiation — which is really just implicit differentiation in disguise.
The core idea: take the natural logarithm of both sides, use log properties to bring the exponent down, then differentiate implicitly. This converts the problem into a product rule inside a chain rule, which is much easier to manage.
- Set up the equation Let , with (so is defined). Take the natural log of both sides:
- Differentiate implicitly with respect to On the left, (by the chain rule). On the right, is a product, so we use the product rule:
Putting it together:
- Solve for Multiply both sides by :
Now substitute back :
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