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Exercise 5.4 · Q3

Q.Differentiate the following w.r.t. xx: ex3e^{x^3}

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We differentiate ex3e^{x^3} using the Chain Rule: treat x3x^3 as the inner function uu, differentiate eue^u to get eue^u, then multiply by the derivative of uu (3x23x^2). The result is 3x2ex33x^2 e^{x^3}.

The key idea here is the Chain Rule. When you have a function of a function — like ee raised to something that itself depends on xx — you can't just differentiate the outer part and stop. You have to peel the layers like an onion: differentiate the outer layer, then multiply by the derivative of the inner layer.

Think of it this way: ex3e^{x^3} is the composition of two functions. The outer function is f(u)=euf(u) = e^u, and the inner function is u(x)=x3u(x) = x^3. The Chain Rule says:

ddxf(u(x))=f′(u(x))⋅u′(x)\frac{d}{dx} f(u(x)) = f'(u(x)) \cdot u'(x)

So we differentiate the outside (keeping the inside untouched), then multiply by the derivative of the inside.

Let's work through it step by step.

  1. Identify the inner function.

    Here, the exponent x3x^3 is the "inside" part. Let u=x3u = x^3. Then our function becomes eue^u.

  2. Differentiate the outer function with respect to its argument.

    The derivative of eue^u with respect to uu is simply eue^u itself. So:

ddu(eu)=eu\frac{d}{du}(e^u) = e^u

This means the derivative of the outer part, evaluated at u=x3u = x^3, is ex3e^{x^3}.

  1. Differentiate the inner function with respect to xx. The derivative of u=x3u = x^3 is:

dudx=3x2\frac{du}{dx} = 3x^2

  1. Multiply the two derivatives (Chain Rule). The Chain Rule tells us:

dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}

Substituting what we have:

dydx=ex3⋅3x2\frac{dy}{dx} = e^{x^3} \cdot 3x^2

  1. Write the final result in standard form. It's conventional to write the constant factor first:

dydx=3x2ex3\frac{dy}{dx} = 3x^2 e^{x^3}

Watch out

A common mistake is to write ex3⋅3x2e^{x^3} \cdot 3x^2 but forget that the derivative of eue^u is eue^u, not eu⋅u′e^u \cdot u' — that extra u′u' comes from the Chain Rule after differentiating the outer function. Another pitfall: trying to treat ex3e^{x^3} like a power function (xnx^n) and using the Power Rule — that would be wrong because the variable is in the exponent, not the base.

Tip

The Chain Rule is your best friend whenever you see a function "wrapped around" another function. A quick mental check: if you had to compute ex3e^{x^3} by hand for a specific xx, you'd first cube xx, then raise ee to that result. The derivative reverses that order: differentiate the last operation first, then multiply by the derivative of the first operation.

✓Final answer

The derivative is 3x2ex3\boxed{3x^2 e^{x^3}}.

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