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NCERT Exemplar · Q64

Q.Family y=Ax+A3y=Ax+A^3 of curves is represented by the differential equation of degree:
(A) 1
(B) 2
(C) 3
(D) 4

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Eliminating AA gives y=xdydx+(dydx)3y=x\frac{dy}{dx}+\left(\frac{dy}{dx}\right)^3, in which the highest-order derivative dydx\frac{dy}{dx} occurs to the power 3, so the degree is 3 — option (C).

Find the differential equation

The family y=Ax+A3y=Ax+A^3 has one arbitrary constant AA. Differentiate once:

dydx=A.\frac{dy}{dx}=A.

So A=dydxA=\frac{dy}{dx}. Substitute this back into y=Ax+A3y=Ax+A^3:

y=xdydx+(dydx)3.y=x\frac{dy}{dx}+\left(\frac{dy}{dx}\right)^3.

Read off the degree …

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