Q.Assume , , , and are matrices of order , , , and , respectively. Then the restriction on , and so that will be defined are:
(A)
(B) is arbitrary,
(C) is arbitrary,
(D)
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Start your 14-day free trial to unlock the full solution →For to be defined, both products must be compatible and the resulting matrices must have the same dimensions. This forces and , making option (A) correct.
The core idea here is matrix multiplication compatibility — the number of columns in the first matrix must equal the number of rows in the second. When adding two matrices, they must also have identical dimensions. So being defined means both and are individually defined, and their results are the same size.
Let’s unpack the given orders:
- :
- :
- :
- :
- :
We only care about , , and .
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Check : is , is . For multiplication , the number of columns of must equal the number of rows of . That means . If , is not defined at all, so the sum cannot exist. So is necessary.
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Check : is , is . With from step 1, becomes . The columns of (3) match the rows of (3), so is defined for any . Its resulting order is .
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Now with : is , is , so is defined and its order is . …
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