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NCERT Exemplar · Q13

Q.A ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet.

(i) In which direction will it move?
(ii) What will be the direction of it's magnetic moment?
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A superconductor is a perfect diamagnet (Meissner effect), so it is repelled by the bar magnet — it moves away toward weaker field — and its induced magnetic moment points opposite to the external field.

Why a superconductor is special

Below its critical temperature a superconductor enters the Meissner state and expels all magnetic flux from its interior. It behaves as a perfect diamagnet with susceptibility χ=−1\chi = -1: whatever field is applied, screening surface currents arise that cancel it inside the material.

(i) Direction of motion

  1. Induced moment opposes the field. The screening currents produce a magnetic moment m⃗\vec{\mathfrak{m}} antiparallel to the applied field B⃗ext\vec{B}_{\text{ext}}.
  2. Force in a non-uniform field. A dipole feels F⃗=∇(m⃗⋅B⃗ext)\vec{F} = \nabla(\vec{\mathfrak{m}}\cdot\vec{B}_{\text{ext}}). Since m⃗\vec{\mathfrak{m}} is antiparallel to B⃗ext\vec{B}_{\text{ext}}, the product m⃗⋅B⃗ext<0\vec{\mathfrak{m}}\cdot\vec{B}_{\text{ext}} < 0, so the force points toward decreasing ∣B⃗ext∣|\vec{B}_{\text{ext}}|.
  3. A bar magnet's field is strongest at the pole and weakens outward, so the ball is pushed toward weaker field — it is repelled and moves away from the magnet.
Watch out

Do not confuse this with a piece of iron, which is ferromagnetic and is attracted. A diamagnet — and a superconductor is the perfect case — is always repelled.

(ii) Direction of the magnetic moment …

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