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NCERT Exemplar · Q4

Q.Fusion processes, like combining two deuterons to form a He nucleus are impossible at ordinary temperatures and pressure. The reasons for this can be traced to the fact:

(a) nuclear forces have short range.
(b) nuclei are positively charged.
(c) the original nuclei must be completely ionized before fusion can take place.
(d) the original nuclei must first break up before combining with each other.
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Both (A) and (B) together are the correct reasons: the nuclear force has a very short range, so two deuterons must approach to within about 1 fm1\ \text{fm} before it can bind them (A) — and because both deuterons are positively charged, the Coulomb repulsion between them prevents that close an approach at ordinary thermal energies (B). Together, these two facts are exactly the "Coulomb barrier" argument for why fusion needs extremely high temperature.

This is an NCERT Exemplar multiple-correct-answer (MCQ-II) question — more than one option can be correct, and here (A) and (B) are both needed together to fully explain why fusion doesn't happen at ordinary temperature and pressure.

Step 1 — Why closeness matters: option (A).

The strong nuclear force that binds nucleons together is attractive, but it acts only over an extremely short range — roughly 1 fm1\ \text{fm} (10−15 m10^{-15}\ \text{m}), comparable to the size of a nucleus itself. Beyond this range it drops off essentially to zero. So for two deuterons to fuse into a helium nucleus, they must first be brought within about 1 fm1\ \text{fm} of each other — only then does the nuclear force take over and pull them together. This is exactly what option (A), "nuclear forces have short range," is telling you.

Step 2 — Why that closeness is blocked: option (B).

A deuteron nucleus carries a net positive charge (+e+e, from its single proton). Two deuterons approaching each other therefore repel electrostatically, via Coulomb's law:

F=14πε0e2r2F = \frac{1}{4\pi\varepsilon_0}\frac{e^2}{r^2}

As the separation rr shrinks toward the ∼1 fm\sim 1\ \text{fm} distance the nuclear force needs, this repulsion grows very large. The height of this "Coulomb barrier" at r≈1 fmr \approx 1\ \text{fm} works out to roughly

U≈14πε0e2r∼0.5 to 1 MeV.U \approx \frac{1}{4\pi\varepsilon_0}\frac{e^2}{r} \sim 0.5 \text{ to } 1\ \text{MeV}.

At ordinary temperature (say 300 K300\ \text{K}), the average thermal kinetic energy of a particle is only kBT≈0.025 eVk_B T \approx 0.025\ \text{eV} — many millions of times too small to climb this barrier. This is exactly what option (B), "nuclei are positively charged," is telling you: it is that positive charge which sets up the barrier in the first place.

Step 3 — Why (A) and (B) must be taken together.

Neither fact alone tells the whole story:

  • (A) alone says the nuclear force's range is short — it explains what the deuterons need to achieve (get to within ∼1 fm\sim 1\ \text{fm} of each other), but not why that is hard to do.
  • (B) alone says the nuclei repel each other — it explains why closeness is resisted, but not how close they actually need to get before that repulsion becomes the deciding obstacle. …

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